JAMB - Physics (1979 - No. 3)
A 500kg car which was initially at rest travelled with an acceleration of 5m sec-2, its kinetic energy after 4 seconds was
105J
2.5 x 103J
2 x 103J
5 x 103J
5 x 105J`
Magyarázat
K.E = \(\frac{1}{2}\)mv2; m (at + u)2
since, v = at + u = \(\frac{1}{2}\) x 500 [(5 x 4)+ 0]2
= 105J
since, v = at + u = \(\frac{1}{2}\) x 500 [(5 x 4)+ 0]2
= 105J