WAEC - Physics (2011 - No. 15)
The radius of a wheel is 30.0 cm and that of its axle is 6.0cm. Calculate the effort required to lift a load of 120.0N using this machine. Assuming 100% efficiency
600.0N
40.0N
24.0N
20.0N
स्पष्टीकरण
V.R = \(\frac{R}{r} = \frac{30}{6} = 5\)
\(\gamma = \frac{M.A}{V.R} \times \frac{100}{1} \)
M.A = \(\frac{100 \times 5}{100} = 5\)
Effort = \(\frac{L}{M.A} = \frac{120}{5}\)
= 24N
\(\gamma = \frac{M.A}{V.R} \times \frac{100}{1} \)
M.A = \(\frac{100 \times 5}{100} = 5\)
Effort = \(\frac{L}{M.A} = \frac{120}{5}\)
= 24N