WAEC - Physics (2002 - No. 8)
A car takes off from rest and covers a distance of 80m on a straight road in 10s. Calculate the magnitude of its acceleration
1.25ms-2
1.60ms-2
4.00ms-2
8.00ms-2
स्पष्टीकरण
s = \(ut + \frac{1}{2}at^2\)
80 = 0 x 10 + \(\frac{1}{2}\) x a x 102
a = \(\frac{80}{50} = 1.6ms^2\)
80 = 0 x 10 + \(\frac{1}{2}\) x a x 102
a = \(\frac{80}{50} = 1.6ms^2\)