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दाखिल करना

WAEC - Physics (2002 - No. 5)

A boy travels 8 km eastward to a point B and then 6km northward to another point C. Determine the difference between the magnitude of displacement of the boy and distance travelled by him
2.0km
4.0km
10.0km
13.0km

स्पष्टीकरण

AC = \(\sqrt{8^2 + 6^2}\) = 10km

Distance travelled = 8 + 6 = 14km

Difference = 4 - 10 = 4km

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