WAEC - Physics (1998 - No. 9)
An object is protected with a velocity of 100m-1 at an angle of 60o to the vertical. Calculate the time taken by the object to reach the highest point (Take g as 10ms-2
5.0s
8.7s
10.0s
17.3s
20.0s
स्पष्टीकरण
t = \(\frac{T}{2} = \frac{1}{2} = \frac{2u \sin \theta}{g} = \frac{100 \times \sin 60}{10}\)
10 sin60 = 10 x 0.8660
= 8.7
10 sin60 = 10 x 0.8660
= 8.7