WAEC - Physics (1994 - No. 37)
An electric kettle rated 1500W boils away 0.3kg of a liquid at its boiling point every 300s. Calculate the specific latent heat of the vaporisation of the liquid
1.5 x \(10^6Jkg^-1\)
1.35 x \(10^6Jkg^-1\)
1.5 x \(10^5Jkg^-1\)
4.5 x \(10^2Jkg^-1\)
3 x \(10^2Jkg^-1\)
स्पष्टीकरण
Pt=mI; I=\(\frac{1500\times300}{0.3}=1.5\times10^6Jkg^-1\)