WAEC - Mathematics (2021 - No. 3)
Solve: 2\(^{\sqrt{2x + 1}}\) = 32
13
24
12
11
स्पष्टीकरण
2\(^{\sqrt{2x + 1}}\) = 32
2\(^{\sqrt{2x + 1}}\) = 2\(^5\)
\(\sqrt{2x + 1}\) = 5
square both sides
2x + 1 = 5\(^2\)
2x + 1 = 25
2x = 25 - 1
2x = 24
x = \(\frac{24}{2}\)
x = 12