WAEC - Mathematics (2012 - No. 10)
Make p the subject of the relation: q = \(\frac{3p}{r} + \frac{s}{2}\)
p = \(\frac{2q - rs}{6}\)
p = 2qr - sr - 3
p = \(\frac{2qr - s}{6}\)
p = \(\frac{2qr - rs}{6}\)
स्पष्टीकरण
q = \(\frac{3p}{r} + \frac{s}{2}\)
q = \(\frac{6p + rs}{2r}\)
6p + rs = 2qr
6p = 2qr - rs
p = \(\frac{2qr - rs}{6}\)
q = \(\frac{6p + rs}{2r}\)
6p + rs = 2qr
6p = 2qr - rs
p = \(\frac{2qr - rs}{6}\)