WAEC - Mathematics (2003 - No. 17)
Find the value of x in the equation 3x\(^2\) - 8x - 3 = 0
\(\frac{1}{3},-3\)
\(-\frac{1}{3},-3\)
\(-\frac{1}{3},3\)
\(\frac{1}{3},3\)
स्पष्टीकरण
3x\(^2\) - 8x - 3 = 0
3x\(^2\) - 9x + x - 3 = 0
3x(x - 3) + 1(x - 3) = 0
(3x + 1)(x - 3) = 0
3x = -1 \(\implies\) x = \(-\frac{1}{3}\)
or x = 3.