WAEC - Mathematics (1997 - No. 32)
Given that \(\frac{1}{2} \log_{10} P = 1\), find the value of P.
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103
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10-1
स्पष्टीकरण
\(\frac{1}{2} \log_{10} P = 1\)
\(\log_{10} P^{\frac{1}{2}} = 1\)
\(P^{\frac{1}{2}} = 10^{1}\)
\(\implies P = 10^{2}\)