WAEC - Mathematics (1990 - No. 31)
In the diagram above PS||RQ, |RQ| = 6.4cm and perpendicular PH = 3.2cm. Find the area of SQR
5.12cm2
9.60cm2
10.24cm2
20.48cm2
40.96cm2
स्पष्टीकरण
Area of a triangle = \(\frac{1}{2} \times b \times h\)
Area of \(\Delta\) SQR = \(\frac{1}{2} \times 6.4 \times 3.2\)
= 10.24 cm\(^2\)