WAEC - Further Mathematics (2013 - No. 2)
Solve: \(\sin \theta = \tan \theta\)
200°
90°
60°
0°
स्पष्टीकरण
\(\sin \theta = \tan \theta \implies \frac{\sin \theta}{1} = \frac{\sin \theta}{\cos \theta}\)
Equating, we have
\(\cos \theta = 1 \implies \theta = \cos^{-1} 1\)
= \(0°\)