WAEC - Further Mathematics (2006 - No. 15)
Evaluate \(\lim \limits_{x \to 1} \frac{1 - x}{x^{2} - 3x + 2}\)
1
\(\frac{1}{2}\)
0
-1
स्पष्टीकरण
\(\lim \limits_{x \to 1} \frac{1 - x}{x^{2} - 3x + 2}\)
\(\frac{1 - x}{x^{2} - 3x + 2} = \frac{-(x - 1)}{(x - 1)(x - 2)}\)
= \(\frac{-1}{x - 2}\)
\(\lim \limits_{x \to 1} \frac{1 - x}{x^{2} - 3x + 2} = \lim \limits_{x \to 1} \frac{-1}{x - 2}\)
= \(\frac{-1}{1 - 2} = \frac{-1}{-1} = 1\)