ExamPlay Light Logo
दाखिल करना

WAEC - Further Mathematics (2006 - No. 1)

\(P = {x : 1 \leq x \leq 6}\) and \(Q = {x : 2 < x < 9}\) where \(x \in R\), find \(P \cap Q\).
\({x : 2 \leq x \leq 6}\)
\({x : 2 \leq x < 6}\)
\({x : 2 < x < 6}\)
\({x : 2 < x \leq 6}\)

टिप्पणियाँ (0)

विज्ञापन