JEE Advance - Physics (1985 - No. 1)
Plank' constant has dimension __________.
MLT
ML2T-2
ML-1T-1
ML2T-1
M2LT-1
स्पष्टीकरण
We know E = hv
So $$h = {E \over v} = {{\left[ {M{L^2}{T^{ - 2}}} \right]} \over {\left[ {{T^{ - 1}}} \right]}} = \left[ {M{L^2}{T^{ - 1}}} \right]$$
So $$h = {E \over v} = {{\left[ {M{L^2}{T^{ - 2}}} \right]} \over {\left[ {{T^{ - 1}}} \right]}} = \left[ {M{L^2}{T^{ - 1}}} \right]$$