दाखिल करना

JEE Advance - Mathematics (1998 - No. 39)

If $$f\left( x \right) = {{{x^2} - 1} \over {{x^2} + 1}},$$ for every real number $$x$$, then the minimum value of $$f$$

does not exist because $$f$$ is unbounded

is not attained even though $$f$$ is bounded

is equal to 1

is equal to -1

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