ExamPlay Light Logo
दाखिल करना

JEE Advance - Mathematics (1984 - No. 29)

The locus of the mid-point of a chord of the circle $${x^2} + {y^2} = 4$$ which subtends a right angle at the origin is
x + y = 2
$${x^2} + {y^2} = 1$$
$${x^2} + {y^2} = 2$$
$$x + y $$=1

टिप्पणियाँ (0)

विज्ञापन