ExamPlay Light Logo
दाखिल करना

JEE MAIN - Physics (2011 - No. 10)

If a wire is stretched to make it $$0.1\% $$ longer, its resistance will:
increase by $$0.2\% $$
decrease by $$0.2\% $$
decrease by $$0.05\% $$
increase by $$0.05\% $$

स्पष्टीकरण

Resistance of wire

$$R = {{\rho l} \over A} = {{\rho {l^2}} \over C}$$ (where $$Al=C$$ )

$$\therefore$$ Fractional charge in resistance

$${{\Delta R} \over R} = 2{{\Delta l} \over l}$$

$$\therefore$$ Resistance will increase by $$0.2\% $$

टिप्पणियाँ (0)

टिप्पणी करने के लिए लॉगिन करें
विज्ञापन
BrainBehindX Inc Logo
©2026; द्वारा संचालित BrainBehindX Inc