JEE MAIN - Physics (2003 - No. 61)
A rocket with a lift-off mass $$3.5 \times {10^4}\,\,kg$$ is blasted upwards with an initial acceleration of $$10m/{s^2}.$$ Then the initial thrust of the blast is
$$3.5 \times {10^5}N$$
$$7.0 \times {10^5}N$$
$$14.0 \times {10^5}N$$
$$1.75 \times {10^5}N$$
स्पष्टीकरण
Here, thrust force is responsible to accelerate the rocket,
So initial thrust of the blast
= (Lift-off mass) × acceleration
= (3.5 × 104) × (10)
= 3.5 × 105 N
So initial thrust of the blast
= (Lift-off mass) × acceleration
= (3.5 × 104) × (10)
= 3.5 × 105 N