JAMB - Physics (2025 - No. 15)
A 500W electric oven plugged into a 220 V source will consume an electric current of
4.88A
2.27A
6.43A
3.23A
स्पष्टीकरण
Answer: B. 2.27A
(I = \(\frac{\text{P}}{\text{V}}\) = \(\frac{500}{220}\) ≈ 2.27 A.)
Answer: B. 2.27A
(I = \(\frac{\text{P}}{\text{V}}\) = \(\frac{500}{220}\) ≈ 2.27 A.)