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JAMB - Physics (2019 - No. 37)

A force of 6N acts horizontally on a stationary mass of 2kg for 4s. The kinetic energy gained by the mass is _________
366j
240j
144j
90j

स्पष्टीकरण

F = 6N, m = 2kg, t = 4s, u = 0 (stationary or at rest)

 

K.E = 1
2
mv\(^2\)

 

F = mv
t

from rest

K.E = 1
2
m( Ft
m
)\(^2\) = 1
2
× 2 x (\(\frac{6 \times 4}{2})^2 = 12^2 = 144J\)

 

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