JAMB - Physics (2017 - No. 28)
4.0 x 10\(^{-2}\)J
4.0 x 10\(^{-4}\)J
8.0 x 10\(^{-4}\)J
8.0 x 10\(^{-2}\)J
स्पष्टीकरण
c = 8µF, v = 10v
Energy stored = \(\frac{1}{2}\) cv2
= \(\frac{1}{2}\) × (8 × 10− 6) × 102
= 4 × 10\(^{-4}\)
Energy stored = \(\frac{1}{2}\) cv2
= \(\frac{1}{2}\) × (8 × 10− 6) × 102
= 4 × 10\(^{-4}\)