JAMB - Physics (2016 - No. 27)
Calculate the temperature of 6 moles of an ideal gas at a pressure of 7.6 x 106Nm-2 with a volume of 10-3m3.
[R = 8.3jmol-1K-1]
[R = 8.3jmol-1K-1]
201oC
126oC
153oC
185oC
स्पष्टीकरण
T = \(\frac{PV}{nR}\) = \(\frac{7.6 x 10^6 x 10^-3}{6 x 8.3}\)
= 153oC
= 153oC