JAMB - Physics (2008 - No. 8)
A motorcycle of mass 100kg moves round in a circle of radius 10m with a velocity of 5 ms-1. find the coefficient of friction between the road and the tyres.
25.00
2.50
0.50
0.25
स्पष्टीकरण
F = (mv)2/r = (100 x 5)2 = 250N
R = mg = 100 x 10 - 1000N
coefficient of friction,
µ = (F)/R = (250)/1000 = 0.25
R = mg = 100 x 10 - 1000N
coefficient of friction,
µ = (F)/R = (250)/1000 = 0.25