ExamPlay Light Logo
दाखिल करना

JAMB - Physics (2007 - No. 27)

In the diagram above, a rod 50 cm long of uniform cross-section is suspended horizontally on a fulcrum, F, by the action of two forces. What is the weight of the rod?
40N
80N
120N
200N

स्पष्टीकरण

Being a uniform rod, the height W should be acting at the mid point 25cm mark.
∴ Taking moment about the fulcrum, F,
200 x 10 = W x 10 + 40 x 30
2000 = 10W + 1200
=> 10W = 2000 - 1200
= 800
w = 800/10 = 80N

टिप्पणियाँ (0)

टिप्पणी करने के लिए लॉगिन करें
विज्ञापन
BrainBehindX Inc Logo
©2026; द्वारा संचालित BrainBehindX Inc