JAMB - Physics (2005 - No. 41)
106J of heat is required to boil off completely 2kg of a certain liquid. Neglecting heat lost to the surroundings, the latent heat of vaporization of the liquid is
2.0 x 106J kg-1
5.0 x 106J kg-1
2.0 x 105J kg-1
5.0 x 105J kg-1
स्पष्टीकरण
From the heat exchange involved, the latent heat of vaporization, L can be deduced from the relation:
ML = 106, where M = mass of the liquid.
∴ 2 x L = 106
=> L = 106/2 = 5.0 x 105J kg-1
ML = 106, where M = mass of the liquid.
∴ 2 x L = 106
=> L = 106/2 = 5.0 x 105J kg-1