JAMB - Physics (2002 - No. 7)
A particle in circular motion performs 30 oscillation in 6 seconds. Its angular velocity is
5 rad s-1
6 rad s-1
5π rad s-1
10π rad s-1
स्पष्टीकरण
Angular velocity w = 2π f.
But f = frequency no. of oscillations per second.
= 30/6 = 5Hz.
therefore W = 2π x 5
= 10π rad. s-1
But f = frequency no. of oscillations per second.
= 30/6 = 5Hz.
therefore W = 2π x 5
= 10π rad. s-1