JAMB - Physics (1998 - No. 20)
How many grams of water at 17oC must be added to 42g of ice at 0oC to melt the ice completely? [specific latent heat of fusion of ice = 3.4 x 105Jkg-1, specific heat capacity of water = 4200Jkg-1k-1]
200g
300g
320g
400g
स्पष्टीकरण
Heat lost = Heat gained
mc\(\theta\) = mL
m x 4200 x 17 = 42 x 3.4 x 105
therefore, m = 200g
mc\(\theta\) = mL
m x 4200 x 17 = 42 x 3.4 x 105
therefore, m = 200g