JAMB - Physics (1998 - No. 12)
The tendon in a man's leg is 0.01m long. If a force of 5N stretches the tendon by 2.0 x 10-5m, calculate the strain on the muscle.
5 x 106
5 x 102
2 x 10-3
2 x 10-7
स्पष्टीकरण
Strain = \(\frac{extension}{\text{original length}}\)
\(\frac{2 {\times} 10^{-5}}{0.01}\)
= 2 x 10-3
\(\frac{2 {\times} 10^{-5}}{0.01}\)
= 2 x 10-3