JAMB - Physics (1994 - No. 23)
A pipe of length 45cm is closed at the end. Calculate the fundamental frequency of the sound wave generated in the pipe if the velocity of sound in air is 360ms-1 [Neglect end correction]
5.5Hz
148.5Hz
200.0Hz
550.0Hz
स्पष्टीकरण
\(\lambda\) = 4L = 4 X 45 = 180cm
F = \(\frac {V}{\lambda}\)
= \(\frac {360}{180 \times 10^{-2}}\)
= 200Hz
F = \(\frac {V}{\lambda}\)
= \(\frac {360}{180 \times 10^{-2}}\)
= 200Hz