JAMB - Physics (1994 - No. 10)
A force of 15N stretches a spring to a total length of 30cm. An additional force of 10N stretches the spring 5cm further. Find the natural length of the spring
25.0cm
22.5cm
20.0cm
15.0cm
स्पष्टीकरण
\(\frac{15}{30 - L}\) = \(\frac{10}{5}\)
L = 22.5cm
L = 22.5cm