JAMB - Physics (1991 - No. 2)
A body of weight W N rest on a smooth plane inclined at an angle\(\theta\)o to the horizontal. What is the resolved part of the weight in Newtons along the plane?
W sin\(\theta\)
W cos\(\theta\)
W sec\(\theta\)
W tan\(\theta\)
स्पष्टीकरण
horizontal component = W cos(90o - \(\theta\))
= W sin
= W sin