JAMB - Physics (1987 - No. 5)
A constant force of 40N acting on a body initially at rest gives an acceleration of 0.1ms-2 for 4s. Calculate the work done by the force
8J
10J
32J
160J
स्पष्टीकरण
X = ut + \(\frac{1}{2}\)at2
= (0 x 4) + (\(\frac{1}{2}\) x 0.1 x 4 x 4)
= 0.8m
workdone = force x distance
= 40 x 0.8
= 32J
= (0 x 4) + (\(\frac{1}{2}\) x 0.1 x 4 x 4)
= 0.8m
workdone = force x distance
= 40 x 0.8
= 32J