JAMB - Physics (1987 - No. 35)
A current of 0.5A flows through a resistor when connected to a 40-V battery. How much energy is dissipated in 2 minutes?
1200J
1500J
2400J
96000J
स्पष्टीकरण
Electrical energy = IVT
= 0.5 x 40 x 2 x 60
= 2400J
= 0.5 x 40 x 2 x 60
= 2400J