JAMB - Physics (1987 - No. 20)
Calculate the amount of heat required to convert 2kg of ice at 2oC to water at 0oC. [specific heat capacity of ice = 2090Jkg-1 oC-1, specific latent heat of fusion of ice = 333kJkg-1]
666J
8360J
666 000J
674 360J
स्पष्टीकरण
Q = mL + mc\(\theta\)
= (2 x 333000) + (2 x 2090 x 2)
= 674 360J
= (2 x 333000) + (2 x 2090 x 2)
= 674 360J