JAMB - Physics (1985 - No. 27)
If the fundamental frequency of a closed pipe organ on a day when the speed of sound is 340ms-1 is 170Hz, then the length of the pipe is
50cm
70cm
100cm
150cm
200cm
स्पष्टीकरण
\(\lambda\) = \(\frac{v}{f}\)
= \(\frac{340}{170}\)
= 2m ; for closed pipe
L = \(\frac{1}{4}\)\(\lambda\)
= \(\frac{1}{4}\) x \(\frac{2}{1}\)
= 0.5m
= 50cm
= \(\frac{340}{170}\)
= 2m ; for closed pipe
L = \(\frac{1}{4}\)\(\lambda\)
= \(\frac{1}{4}\) x \(\frac{2}{1}\)
= 0.5m
= 50cm