JAMB - Physics (1982 - No. 5)
The tyre pressure of a car was found to be 150cmHg in the morning at a temperature of 27°C. Hard driving in the afternoon raised the temperature of the tyres to 57°C. The tyre pressure had by the afternoon was?
increased by 15.0cm Hg
decreased by 15.0cm Hg
increased by 22.50cm
decreased by 22.50cm Hg
remained constant
स्पष्टीकरण
\(\frac{P_1}{T_1}\) = \(\frac{P_2}{T_2}\) at constant volume
\(\frac{150}{27 + 273}\) = \(\frac{P_1}{57 + 273}\)
P2 = 165cmHg
\(\frac{150}{27 + 273}\) = \(\frac{P_1}{57 + 273}\)
P2 = 165cmHg