JAMB - Mathematics (2009 - No. 15)

Find the range of values of x for which 3x - 7 \(\leq\) 0 and x + 5 > 0?

-5 < x < \(\frac{7}{3}\)

-5 \(\leq\) x \(\leq\) \(\frac{7}{3}\)

-5 < x \(\leq\) \(\frac{7}{3}\)

-5 \(\leq\) x < \(\frac{7}{3}\)

3x - 7 \(\leq\) 0 and x + 5 > 0
3x \(\leq\) 7 and x > -5
x \(\leq\) \(\frac{7}{3}\)
∴ Range -5 < x \(\leq\) \(\frac{7}{3}\)