JAMB - Mathematics (2008 - No. 34)
Evaluate \(\int_1 ^2(6x^2-2x)dx\)
16
13
12
11
स्पष्टीकरण
\(\int_1 ^2(6x^2-2x)\)dx = \(\frac{6x^3}{3}-\frac{2x^2}{2}]_1 ^2\)
= \(2x^3 - x^2)_1^2\)
= [2(2)3 - (2)2] – [2(1)3 - (1)2]
= [16-4] – [2-1]
= 12 – 1
= 11
= \(2x^3 - x^2)_1^2\)
= [2(2)3 - (2)2] – [2(1)3 - (1)2]
= [16-4] – [2-1]
= 12 – 1
= 11