JAMB - Mathematics (2003 - No. 7)
Simplify \(\frac{\sqrt{98} - \sqrt{50}}{\sqrt{32}}\)
3
1
\(\frac{1}{2}\)
\(\frac{1}{4}\)
स्पष्टीकरण
\(\frac{\sqrt{98} - \sqrt{50}}{\sqrt{32}}\) = \(\frac{\sqrt{49 \times 2} - \sqrt{25 \times 2}}{\sqrt{16 \times 2}}\)
=> \(\frac{7\sqrt{2} - 5\sqrt{2}}{4\sqrt{2}}\) = \(\frac{2\sqrt{2}}{4\sqrt{2}}\) = \(\frac{1}{2}\)
=> \(\frac{7\sqrt{2} - 5\sqrt{2}}{4\sqrt{2}}\) = \(\frac{2\sqrt{2}}{4\sqrt{2}}\) = \(\frac{1}{2}\)