ExamPlay Dark Logo
दाखिल करना

JAMB - Mathematics (2003 - No. 35)

An aeroplane flies due north from airport P to Q and then flies due east R. If Q is equidistant from P and R, find the bearing of P and R
90o
135o
225o
270o

स्पष्टीकरण

Since PQ = QR, Δ PQR is a right angle isosceles triangle
∴ ∠PQR = 45o
=> The bearing of P from R = 180 + 45
= 225o

टिप्पणियाँ (0)

विज्ञापन