JAMB - Mathematics (2003 - No. 29)
Find the mean of the distribution above
1
2
3
4
स्पष्टीकरण
Mean = \(\frac{(0 \times 1) + (1 \times 2) + (2 \times 2) + (3 \times 1) + (4 \times 9)}{1 + 2 + 2 + 1 + 9}\)
= \(\frac{(0 + 2 + 4 + 3 + 36)}{15}\)
= \(\frac{45}{15}\) =3