JAMB - Mathematics (1993 - No. 43)
In the diagram, PQRS is a circle with O as centre and PQ||RT. If RTS = 32°. Find PSQ
32o
45o
58o
90o
स्पष्टीकरण
< PSO = \(\frac{1}{2}\) < SOQ = \(\frac{1}{2}\)(180) = 90°
< RTS = < PQS = 32° (Alternative angle)
< PSQ = 90 - < PSQ = 90° - 32°
= 58°
< RTS = < PQS = 32° (Alternative angle)
< PSQ = 90 - < PSQ = 90° - 32°
= 58°