JAMB - Mathematics (1988 - No. 33)
The solution of the quadratic equation px2 + qx + b = 0 is
\(\sqrt{\frac{-b \pm b^2 - 4ac}{2a}}\)
\(\frac{-b \pm \sqrt{ p^2 - 4pb}}{2a}\)
\(\frac{-q \pm \sqrt{ q^2 - 4bp}}{2p}\)
\(\frac{-q \pm \sqrt{ p^2 - 4bp}}{2p}\)
स्पष्टीकरण
px2 + qx + b = 0
Using almighty formula
\(\frac{-b \pm \sqrt{ b^2 - 4ac}}{2a}\).........(i)
Where a = p, b = q and c = b
substitute for this value in equation (i)
= \(\frac{-q \pm \sqrt{ q^2 - 4bp}}{2p}\)
Using almighty formula
\(\frac{-b \pm \sqrt{ b^2 - 4ac}}{2a}\).........(i)
Where a = p, b = q and c = b
substitute for this value in equation (i)
= \(\frac{-q \pm \sqrt{ q^2 - 4bp}}{2p}\)