WAEC - Mathematics (2001 - No. 12)
A man is four times as old as his son. The difference between their ages is 36 years Find the sum of their ages
45 years
48 years
60 years
74 years
הֶסבֵּר
Let the sons age be x. The father is 4x
∴ 4x - x = 36; 3x = 36; x = 12
The son is 12 years and the father is 12 x 4 = 48.
The sum of their ages (12 + 48) years = 60years
∴ 4x - x = 36; 3x = 36; x = 12
The son is 12 years and the father is 12 x 4 = 48.
The sum of their ages (12 + 48) years = 60years