WAEC - Mathematics (1990 - No. 22)
Find the value of m which makes x\(^2\) + 8 + m a perfect square
2
4
8
12
16
הֶסבֵּר
x\(^2\) + 8 + m
To make it a perfect square, we add \((\frac{b}{2})^2\)
= \((\frac{8}{2})^2\)
= 16
x\(^2\) + 8 + m
To make it a perfect square, we add \((\frac{b}{2})^2\)
= \((\frac{8}{2})^2\)
= 16