WAEC - Further Mathematics (2012 - No. 26)
A fair die is tossed twice. Find the probability of obtaining a 3 and a 5.
\(\frac{5}{12}\)
\(\frac{2}{3}\)
\(\frac{1}{18}\)
\(\frac{1}{36}\)
הֶסבֵּר
P(c and e) = \(P(c) \times P(e)\)
P(3) = \(\frac{1}{6}\)
P(5) = \(\frac{1}{6}\)
P(3 and 5) = \frac{1}{6} \times \frac{1}{6} = \frac{1}{36}\)