JAMB - Mathematics (2022 - No. 1)
Solve for k in the equation \(\frac{1}{8}^{k+2}\) = 1
2
-4
-2
4
הֶסבֵּר
\((8^{-1})^{k+2}\) = \((8^{0})\)
base 8 cancel out on both sides
-1(k+2) = 0
-k -2 = 0
: k = -2
\((8^{-1})^{k+2}\) = \((8^{0})\)
base 8 cancel out on both sides
-1(k+2) = 0
-k -2 = 0
: k = -2