JAMB - Mathematics (2006 - No. 5)
Find the variance of 2x, 2x-1 and 2x+1
2/3
2
√(2/3)
1
הֶסבֵּר
\(\sum x = 6x\)
\(\sum(x-\bar{x})^2\) = 2
\(\bar{x} = \frac{\sum x}{n}\)
= \(\frac{6x}{3}\)
= 2x
Variance = \(\frac{\sum(x-\bar{x})^2}{n}\)
= \(\frac{2}{3}\)