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JAMB - Mathematics (1997 - No. 39)

A number is selected at random between 10 and 20, both numbers inclusive. Find the probability that the number is an even number
\(\frac{5}{11}\)
\(\frac{1}{2}\)
\(\frac{6}{11}\)
\(\frac{7}{10}\)

הֶסבֵּר

n(even numbers between 10 and 20 inclusive) = 6

n(numbers between 10 and 20) = 11

P(even) = \(\frac{6}{11}\)

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